正激變壓器的設計
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(6). CHECKΔB之選擇合理性.
ΔB=[Vin(min)×Dmax×Ts]/ (Np×Ae)
=(209×6.33)/ (33×194)=0.2067T5、計算線徑：
(1).求初級線徑dwp：
Ip = Pi / VL = Po / (η×Dmax×VIN) =294/(0.80×0.38×209) = 4.63 A
Iprms= Ip×√D =4.63×√0.38 = 2.854A
Awp = I/J = 2.854/5 = 0.571mm2
dwp=√(4Awp/π)＝√(4×0.571/3.14)=0.853mm
Φ0.9mm orΦ0.55mm×4
(2).求NR繞組線徑dwR.
NR=33TSL = N2×AL
L = 332×4690×0.75 = 3.83mH
Im = Vin(min)×ton / L = (209×6.33) / (3.83×103)≈0.345A
AWN = 0.345 / 5 = 0.0691mm2
dwN=√(4×0.0691/3.14) =0.235mm取Φ0.28mm
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